Calvin has twice as many dimes as nickels. If he has a total of $4, how many nickels does he have?

To determine how many nickels Calvin has, we can set up a few equations based on the information provided.

Let’s denote the number of nickels as ( n ). According to the problem, Calvin has twice as many dimes as nickels, so the number of dimes would be ( 2n ).

The values of nickels and dimes are as follows:

• The value of a nickel is $0.05, so the total value of ( n ) nickels is ( 0.05n ).
• The value of a dime is $0.10, therefore the total value of ( 2n ) dimes is ( 0.10(2n) = 0.20n ).

The total value of both types of coins combined is $4, creating the equation:

[ 0.05n + 0.20n = 4 ]

Combining like terms gives us:

[ 0.25n = 4 ]

To solve for ( n ), we can divide both sides by 0.25:

[ n = \frac{4}{0.25} = 16 ]

Thus, Calvin has