Calvin has twice as many dimes as nickels. If he has a total of $4, how many nickels does he have?

Calvin has twice as many dimes as nickels. If he has a total of $4, how many nickels does he have?

• A. 16
• B. 12
• C. 20
• D. 14

Answer: (A)

To determine how many nickels Calvin has, we can set up a few equations based on the information provided. Let’s denote the number of nickels as \( n \). According to the problem, Calvin has twice as many dimes as nickels, so the number of dimes would be \( 2n \). The values of nickels and dimes are as follows: - The value of a nickel is $0.05, so the total value of \( n \) nickels is \( 0.05n \). - The value of a dime is $0.10, therefore the total value of \( 2n \) dimes is \( 0.10(2n) = 0.20n \). The total value of both types of coins combined is $4, creating the equation: \[ 0.05n + 0.20n = 4 \] Combining like terms gives us: \[ 0.25n = 4 \] To solve for \( n \), we can divide both sides by 0.25: \[ n = \frac{4}{0.25} = 16 \] Thus, Calvin has

To determine how many nickels Calvin has, we can set up a few equations based on the information provided.

Let’s denote the number of nickels as ( n ). According to the problem, Calvin has twice as many dimes as nickels, so the number of dimes would be ( 2n ).

The values of nickels and dimes are as follows:

• The value of a nickel is $0.05, so the total value of ( n ) nickels is ( 0.05n ).

• The value of a dime is $0.10, therefore the total value of ( 2n ) dimes is ( 0.10(2n) = 0.20n ).

The total value of both types of coins combined is $4, creating the equation:

[

0.05n + 0.20n = 4

]

Combining like terms gives us:

[

0.25n = 4

]

To solve for ( n ), we can divide both sides by 0.25:

[

n = \frac{4}{0.25} = 16

]

Thus, Calvin has